Final answer:
The final velocity of the 110 g hockey puck after colliding with a 420 g water bottle that moves at 0.84 m/s is -1.008 m/s, with the negative sign indicating a reversal of direction.
Step-by-step explanation:
The student asked what the final velocity of a 110 g hockey puck would be after it collides with a 420 g water bottle which then moves at 0.84 m/s. To solve this, we can use the conservation of momentum, which states that the total momentum before the collision is the same as the total momentum after the collision if no external forces are acting on the system.
The initial momentum of the puck is (0.110 kg) × (2.2 m/s) = 0.242 kg·m/s, and the initial momentum of the water bottle is zero since it was at rest. Let v_puck be the final velocity of the puck after the collision. The final momentum of the water bottle is (0.420 kg) × (0.84 m/s) = 0.3528 kg·m/s. By the conservation of momentum:
Initial momentum of puck + Initial momentum of bottle = Final momentum of puck + Final momentum of bottle
0.242 kg·m/s + 0 = (0.110 kg) × v_puck + 0.3528 kg·m/s
Solving for v_puck:
v_puck = (0.242 kg·m/s - 0.3528 kg·m/s) / 0.110 kg = -1.008 m/s
The negative sign indicates that the puck has reversed direction after the collision.