Question

An electric motor raises a load of 0.2 kg, at a constant speed, through a vertical distance of 3.0 m in 2. the acceleration of free fall is 10 m/s2, the power in W developed by the motor in raising the load is

(a) 0.3
(b) 1.2
(c) 3.0
(d) 6.041.

Answer 1

The power developed by the electric motor in raising the load is 3.0 W.

Step-by-step explanation:

The power developed by the electric motor in raising the load can be calculated using the equation:

Power (P) = Work done (W) / Time (t)

The work done can be calculated as the product of the force applied and the distance moved. In this case, the force is equal to the weight of the load, which can be calculated as the product of the mass and acceleration due to gravity.

So, the power developed by the motor is given by:

P = (0.2 kg * 10 m/s2 * 3.0 m) / 2 s = 3.0 W

Therefore, the correct option is (c) 3.0.