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create a number that has a seven in the place value that is 100 times greater than the seven In 56.792​

User Alexmeia
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1 Answer

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Final answer:

To create a number with a seven 100 times greater than the seven in 56.792, we must move the 7 two places to the left, resulting in the number 5769.2.

Step-by-step explanation:

The student's question involves understanding the place value system in mathematics and how to manipulate numbers according to that system. In the number 56.792, the digit 7 is in the tenths place, which is the first decimal place. To create a number with a seven in the place value that is 100 times greater, we would have to move the 7 two places to the left, because each place to the left is 10 times greater than the one to its right, and thus 10 x 10 = 100 times greater overall. This results in the 7 being in the thousands place.

If we were to create such a number without altering the other digits and their relative positions, we could take the number 56.792, and represent it as 5679.2, which effectively multiplies the 7 by 100, moving it to the thousands place. Therefore, the number we're looking for is 5769.2.

User Gyim
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