Final answer:
The final velocity of an object that accelerates from rest at 5 m/s² for a distance of 250 m is 50 m/s, calculated by using the kinematic formula v_f = √(2ad) with given values.
Step-by-step explanation:
To find the final velocity of an object that accelerates from rest, you can use the kinematic equation that relates acceleration (a), initial velocity (vi), final velocity (vf), and distance (d). Since the initial velocity is zero (the object is starting from rest), the equation simplifies to vf = √(2ad). Substituting the given values into this equation:
vf = √(2 × 5 m/s2 × 250 m)
vf = √(2 × 1250)
vf = √(2500)
vf = 50 m/s
The final velocity of the object after accelerating for a distance of 250 meters at 5 m/s2 from rest is 50 meters per second