Question

When Kevin was caught in a thunderstorm, he accelerated uniformly from a velocity of 2.1 m/s to 5.2 m/s in 5.6 5. How far did he

Travels during this time?

Answer 1

To find the distance Kevin travels during the time he accelerates, we can use the formula: Distance = (Final Velocity - Initial Velocity) * Time. Plugging in the values, we get: Distance = (5.2 m/s - 2.1 m/s) * 5.6 s = 3.1 m/s * 5.6 s = 17.36 meters. So, Kevin travels approximately 17.36 meters during this time period.

Step-by-step explanation:

To find the distance Kevin travels during the time he accelerates, we can use the formula:

Distance = (Final Velocity - Initial Velocity) * Time

Plugging in the values, we get:

Distance = (5.2 m/s - 2.1 m/s) * 5.6 s = 3.1 m/s * 5.6 s = 17.36 meters

So, Kevin travels approximately 17.36 meters during this time period.