Question

A container of NO_2 that is initially at STP has a volume of 3.5 L. If the temperature decreases to 200.0 K, what will be the new volume?

a) 2.6 mL
b) 2.6 L
c) 0.39 mL
d) 0.39 L

Answer 1

The new volume of the container would be 2.6 L.

Step-by-step explanation:

To find the new volume of the container, we can use the combined gas law equation:

P1V1/T1 = P2V2/T2

The initial temperature is 273 K at STP and the initial volume is 3.5 L. The final temperature is 200 K. Plugging these values into the equation, we get:

(1 atm)(3.5 L)/(273 K) = (1 atm)(V2)/(200 K)

Solving for V2, the final volume, we get V2 = 2.6 L.