Question

In a race, Car #1 went an average of 255 kilometers per hour for x hours before dropping out. Car #2 went an average of 265 kilometers per hour for y hours before dropping out. The distance Car #1 travelled was greater than that of Car #2. Using the values and variables given, write an inequality describing this.

Answer 1

The inequality showing that Car #1 travelled a greater distance than Car #2 is 255x > 265y, using the distances travelled by each car calculated by their respective speeds and times.

Step-by-step explanation:

To write an inequality describing the situation where Car #1 travelled a greater distance than Car #2 before dropping out, we should use the formula for distance, which is the product of average speed and time. Given that Car #1 went an average of 255 kilometers per hour for x hours and Car #2 went an average of 265 kilometers per hour for y hours, the distances travelled by Car #1 and Car #2 are 255x and 265y kilometers respectively.

The inequality stating that Car #1 travelled a greater distance than Car #2 before dropping out is:

255x > 265y

This inequality can be interpreted as for Car #1 to have travelled a greater distance than Car #2, the product of Car #1's average speed (255 km/h) and the time it travelled (x hours) must be greater than the product of Car #2's average speed (265 km/h) and the time it travelled (y hours).