Question

Calculate how many moles of NO2 form when each quantity of reactant completely reacts via the following reaction: 2N2O5(g)→4NO2(g)+O2(g)

1) 2.4 mol N2O5
2)6.4 mol N2O5
3)15.8 g N2O5
4)3.75 kg N2O5

Answer 1

Using stoichiometry, we calculate moles of NO2 produced from given moles or mass of N2O5. the reactions are: 2.4 moles N2O5 gives 4.8 moles NO2, 6.4 moles N2O5 gives 12.8 moles NO2, 15.8 g N2O5 gives 0.2926 moles NO2, and 3.75 kg N2O5 gives 69.442 moles NO2.

Step-by-step explanation:

To calculate how many moles of NO2 form when each quantity of N2O5 reactant completely reacts via the reaction 2N2O5(g) → 4NO2(g) + O2(g), we use the stoichiometry of the balanced equation. the molar ratio between N2O5 and NO2 is 2:4, meaning 1 mole of N2O5 will produce 2 moles of NO2.

• For 2.4 moles of N2O5: 2.4 moles N2O5 × (4 moles NO2 / 2 moles N2O5) = 4.8 moles NO2
• For 6.4 moles of N2O5: 6.4 moles N2O5 × (4 moles NO2 / 2 moles N2O5) = 12.8 moles NO2
• For 15.8 grams of N2O5: Convert mass to moles using molar mass of N2O5 (108.01 g/mol), then calculate moles of NO2. 15.8 g N2O5 ÷ 108.01 g/mol = 0.1463 moles N2O5, which yields 0.1463 moles N2O5 × (4 moles NO2 / 2 moles N2O5) = 0.2926 moles NO2
• For 3.75 kg of N2O5: Convert kilograms to grams, then to moles. 3.75 kg × 1000 g/kg = 3750 g N2O5, then 3750 g N2O5 / 108.01 g/mol = 34.721 moles N2O5, which yields 34.721 moles N2O5 × (4 moles NO2 / 2 moles N2O5) = 69.442 moles NO2