Question

A sample of sulfur dioxide (SO2) is initially at a temperature of 133'C. a volume of 20 L, and a pressure of 850 torr. If the volume changes to 25 L and the temperature increases to 191'C, find the new pressure. *

Answer 1

To find the new pressure of sulfur dioxide (SO2) after the volume and temperature change, use the combined gas law. Convert temperatures to Kelvin, then rearrange and plug the values into the equation to solve for the new pressure, which is 666.05 torr.

Step-by-step explanation:

To find the new pressure of a sample of sulfur dioxide (SO2) after its volume and temperature have changed, we can use the combined gas law, which expresses the relationship between pressure, volume, and temperature of a gas. The combined gas law is P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature. The temperatures must be in Kelvin for the gas law calculations.

First, we convert the temperatures from Celsius to Kelvin by adding 273.15:

• T1 = 133 + 273.15 = 406.15 K
• T2 = 191 + 273.15 = 464.15 K

Using the given values:

• P1 = 850 torr
• V1 = 20 L
• P2 = ? (What we're looking for)
• V2 = 25 L

We rearrange the combined gas law to solve for P2:

P2 = P1V1T2/(T1V2)

Plugging in the values:

P2 = (850 torr * 20 L * 464.15 K) / (406.15 K * 25 L)

P2 = 666.05 torr

Thus, the new pressure of the gas after expanding to 25 L and heating to 191'C is 666.05 torr.