221k views
0 votes
John Jacob Jingleheimer Thompson got onto his rocket sied. After the sled was traveling at 9 m/s, he engaged the engines which accelerated the rocket at 15 m/s2. How fast was john moving after 7 seconds?

1 Answer

4 votes

Final answer:

Using the kinematic equation, the final velocity of John's rocket sled after accelerating at 15 m/s² for 7 seconds, starting from 9 m/s is 114 m/s.

Step-by-step explanation:

The student is asking a physics-related question about the velocity of a rocket sled after it has accelerated for a certain amount of time. To calculate the final velocity, we use the kinematic equation: final velocity = initial velocity + (acceleration × time). In this scenario, John's initial velocity is 9 m/s, the acceleration is 15 m/s2, and the time is 7 seconds. Plugging the values into the equation, we get: final velocity = 9 m/s + (15 m/s2 × 7 s) = 9 m/s + 105 m/s = 114 m/s.

User Dannyyy
by
7.5k points