Question

A droid loses power and rolls down the entry ramp of a spaceship at 1.5 m/s². How far does it travel down the ramp after 2 seconds?

Answer 1

Using the equation of motion for uniformly accelerated motion, and given that the droid starts from rest with an acceleration of 1.5 m/s² for 2 seconds, the droid travels 6 meters down the ramp.

Step-by-step explanation:

To determine how far the droid travels down the ramp after 2 seconds, we need to use the equation of motion for uniformly accelerated motion, which is s = ut + \( \frac{1}{2} \)at^2, where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time. Assuming the droid starts from rest, the initial velocity (u) is 0, the acceleration (a) is 1.5 m/s², and the time (t) is 2 seconds.

Plugging these values into the equation, we get:

s = 0 \( \times \) 2 + \( \frac{1}{2} \) \( \times \) 1.5 m/s² \( \times \) (2 s)^2

s = \( \frac{1}{2} \) \( \times \) 1.5 m/s² \( \times \) 4 s²

s = 3 m/s² \( \times \) 2 s²

s = 6 m

Therefore, the droid travels 6 meters down the ramp after 2 seconds.