202k views
3 votes
Using the quadratic formula to solve x² = 5 – X, what are the values of x?

User Rachie
by
7.9k points

1 Answer

3 votes

Final answer:

The equation x² = 5 - x, when rearranged into standard form x² + x - 5 = 0 and solved using the quadratic formula, yields two solutions: x = (-1 + √21) / 2 and x = (-1 - √21) / 2.

Step-by-step explanation:

To solve the given quadratic equation x² = 5 - x using the quadratic formula, we should first rearrange it into the standard quadratic form ax² + bx + c = 0. We can do this by adding x to both sides of the original equation, resulting in x² + x - 5 = 0. Now we have a = 1, b = 1, and c = -5. Applying the quadratic formula, which is x = (-b ± √(b² - 4ac)) / (2a), we can calculate the two possible values for x.

Substituting our values into the formula gives us:

x = (-(1) ± √((1)² - 4(1)(-5))) / (2(1))

That simplifies to:

x = (-1 ± √(1 + 20)) / 2

x = (-1 ± √21) / 2

This yields two solutions for x:

Therefore, the equation x² = 5 - x has two solutions, which are the values found above using the quadratic formula.

User Kevin Wilson
by
8.1k points