Question

How much energy in Joules, does 80 (g) grams of water at an initial

temperature of 40°C need to absorb to have its temperature raised to a final
temperature of 60 °C ?*
a.6,288J
b.6,488J
c.6,688J
d.7,288J

Answer 1

The amount of energy needed to heat 80 g of water from 40 °C to 60 °C is 6,688 J.

Step-by-step explanation:

The specific heat of water is 4.184 J/g °C, so to heat 1 g of water by 1 °C requires 4.184 J.

Using this information, we can calculate the amount of energy needed to heat 80 g of water from 40 °C to 60 °C.

Energy = (Specific Heat) x (Mass) x (Change in Temperature)

= (4.184 J/g °C) x (80 g) x (60 °C - 40 °C)

= 6,688 J.

Therefore, the correct answer is option c. 6,688 J.