Question

Solve the following-
1) f−5g=25−f
2) 3b−100=6b
3) 4(14+c)=a²

Answer 1

To solve these equations: f - 5g = 25 - f, 3b - 100 = 6b, and 4(14 + c) = a², you can use algebraic methods to isolate the variables and find their values.

Step-by-step explanation:

To solve the given equations:

1. For f - 5g = 25 - f, we can simplify it to 2f - 5g = 25. Now, we isolate the f term by adding 5g to both sides: 2f = 25 + 5g. Finally, divide by 2 to solve for f: f = (25 + 5g)/2.
2. For 3b - 100 = 6b, we can start by isolating the b term. Subtract 3b from both sides: -100 = 3b - 6b. Simplify to get -100 = -3b. Divide by -3 to solve for b: b = -100/-3 = 100/3.
3. For 4(14 + c) = a², we start by simplifying the left side: 56 + 4c = a². Now, take the square root of both sides to solve for a: a = ±√(56 + 4c).