Final answer:
To find the change in elevation between kilometer 6 and kilometer 12, subtract the elevation at kilometer 6 from the elevation at kilometer 12. The change in density of air for each 1,000 meters is approximately -0.0001035 kilograms/cubic meter. Therefore, the change in elevation between kilometer 6 and kilometer 12 is -0.000621 kilograms/cubic meter.
Step-by-step explanation:
To find the change in elevation between kilometer 6 and kilometer 12, we need to subtract the elevation at kilometer 6 from the elevation at kilometer 12. Based on the information given, the rise (change in vertical variable) is 0.100 - 0.307 = -0.207 and the run (change in horizontal variable) is 6,000 - 4,000 = 2,000. Using these values, we can find the slope between the two points, which represents the change in density of air for each 1,000 meters.
The slope is calculated by dividing the rise by the run: -0.207/2,000 = -0.0001035. This means that for each 1,000 meters of distance, the density of air decreases by approximately 0.0001035 kilograms/cubic meter. To find the change in elevation between kilometer 6 and kilometer 12, we can multiply this value by 6 (the difference in distance between the two points): -0.0001035 x 6 = -0.000621 kilograms/cubic meter.