Question

What mass of Potassium chloride(MM=74.55 g/mol) is produced from the reaction of 2.0 G of potassium carbonate(138.21 g/mol) in 2.0 G of hydrochloric acid(MM=36.46 g/mol)?

Answer 1

The mass of potassium chloride produced from the reaction of 2.0 g of potassium carbonate with 2.0 g of hydrochloric acid is 4.094 g, given that hydrochloric acid is the limiting reactant.

Step-by-step explanation:

The question is asking for the mass of potassium chloride produced from the reaction given the mass of reactants. To solve this, we need to write a balanced chemical equation for the reaction between potassium carbonate and hydrochloric acid to produce potassium chloride and water:

K2CO3 + 2 HCl → 2 KCl + H2O + CO2

First, calculate the moles of each reactant using the molar mass:

• Moles of potassium carbonate: 2.0 g / 138.21 g/mol = 0.01447 mol
• Moles of HCl: 2.0 g / 36.46 g/mol = 0.05489 mol

From the equation, it is clear that the stoichiometric ratio of K2CO3 to KCl is 1:2; however, in this case, HCl is the limiting reactant as we need 2 moles of HCl for every mole of K2CO3.

• Therefore, the moles of KCl produced would be the same as the moles of HCl which is 0.05489 mol.

Finally, convert the moles of KCl to grams:

Mass of KCl = moles of KCl × molar mass of KCl = 0.05489 mol × 74.55 g/mol = 4.094 g

So, 4.094 g of potassium chloride is produced from the reaction of 2.0 g of potassium carbonate with 2.0 g of hydrochloric acid.