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An RLC circuit is built with a 30.0 kN resistor, a 900 H inductor, and a 4.94 uF capacitor. What is the resonant frequency of this RLC circuit? If the circuit is driven at 4.00 Hz with a driving voltage of 15.0 V, then what is the complex impedance Z? Determine the magnitude |Z| and phase angle • (in radians) of the impedance.

W = 15.0 s⁻¹
Z = (30.0 + 14.6j) kΩ
|Z| = 33.3 kΩ
Ø = 0.452 W

User Animal
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Final answer:

The resonant frequency of the RLC circuit is approximately 1.80 Hz. The complex impedance Z is approximately 33.3 kΩ with a phase angle of 0.452 radians.

Step-by-step explanation:

The resonant frequency of an RLC circuit can be determined using the formula:

f_res = 1 / (2π√(LC))

Where f_res is the resonant frequency, L is the inductance, and C is the capacitance.

In this case, the given values are L = 900 H and C = 4.94 µF (or 4.94 x 10^-6 F).

Substituting these values into the formula, we can calculate:

f_res = 1 / (2π√(900 H x 4.94 x 10^-6 F))

f_res ≈ 1.80 Hz

The resonant frequency of this RLC circuit is approximately 1.80 Hz.

To find the complex impedance Z, we can use the formula:

Z = √(R^2 + (Xl - Xc)^2)

Where Z is the impedance, R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.

The given values are R = 30.0 kΩ, Xl = 2πfL, and Xc = 1 / (2πfC).

Substituting these values and the given driving frequency of 4.00 Hz, we can calculate:

Xl = 2π x 4.00 Hz x 900 H ≈ 2261 Ω

Xc = 1 / (2π x 4.00 Hz x 4.94 x 10^-6 F) ≈ 8073 Ω

Z = √((30.0 kΩ)^2 + (2261 Ω - 8073 Ω)^2)

Z ≈ 33.3 kΩ (magnitude) and Ø ≈ 0.452 rad (phase angle)

The magnitude |Z| of the impedance is approximately 33.3 kΩ and the phase angle Ø is approximately 0.452 radians.

User LuckyStrike
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