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line m, has the equation y=-3x+8. line m² is parrallel to line m¹ and passes through the point (6,2). what is the equation of m²?

User Wlindner
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1 Answer

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Final answer:

To find the equation of line parallel to line m and passing through the point (6,2), you can use the point-slope form of a linear equation. The equation of line m² is y = -3x + 20.

Step-by-step explanation:

To find the equation of line m², we need to determine its slope and y-intercept. Since line m² is parallel to line m¹, they will have the same slope. The slope of line m₁ is -3, so the slope of line m² will also be -3. Now, we can use the point-slope form of a linear equation to find the equation of line m². Plugging in the values, we get:

y - y₁ = m(x - x₁)

y - 2 = -3(x - 6)

y - 2 = -3x + 18

y = -3x + 20

Therefore, the equation of line m² is y = -3x + 20.

User FallAndLearn
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