Question

Suppose that the distance between the plates of the capacitor is 2.0 mm and the area of each plate is 5.0 × 10 ―3m2. Determine: the electrical field

Answer 1

The electric field strength between the plates of a parallel plate capacitor can be determined using the equation E = Q / (ε₀ * A). In this case, with no charge on the capacitor plates, the electric field strength is 0 N/C.

Step-by-step explanation:

The electric field strength between the plates of a parallel plate capacitor can be determined using the equation:

E = Q / (ε₀ * A)

Where E is the electric field strength, Q is the charge on the capacitor plates, ε₀ is the permittivity of free space, and A is the area of each plate.

In this case, the distance between the plates is 2.0 mm, which is equal to 0.002 m. The area of each plate is 5.0 × 10-3 m2.

Assuming there is no charge on the capacitor plates, the electric field strength between the plates is:

E = 0 / (8.85 × 10-12 * (5.0 × 10-3)) = 0 N/C

Therefore, the electric field strength between the plates is 0 N/C when there is no charge on the capacitor plates.

Answer 2

The electrical field between the plates of the capacitor is 2500 N/C.

Step-by-step explanation:

To determine the electrical field (E) between the plates of the capacitor, we can use the formula:
`\( E = (V)/(d) \)`, where
`\( V \)` is the voltage across the plates and
`\( d \)` is the distance between the plates. In this case, the distance
`(\( d \))` is given as 2.0 mm, which needs to be converted to meters
`(\( 2.0 \, \text{mm} = 0.002 \, \text{m} \))`.

Now, let's assume a typical voltage across the capacitor plates (not explicitly given in the question) and proceed with the calculation. If
`( V = 5 \, \text{V} \)`, then
`\( E = \frac{5 \, \text{V}}{0.002 \, \text{m}} = 2500 \, \text{N/C} \).`

The electrical field represents the force experienced by a unit positive charge between the plates. In this scenario, as the distance between the plates decreases, the electrical field strength increases, resulting in a higher force on the charges.

It's important to note that the electrical field is influenced by factors such as voltage, distance, and the characteristics of the material between the plates. The formula
`\( E = (V)/(d) \)` is a fundamental relationship used to calculate the electrical field in a capacitor.