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Unless stated otherwise, we assign the potential due to a point charge to be zero at an infinite distance from the charge. 1. What is the flux through a sphere of radius f=5.0 cm that has a point charge q=−2.0pcat its center?

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Final answer:

To find the flux through a sphere of radius 5.0 cm with a point charge of -2.0×10^12 C at its center, we can use Gauss's Law.

Step-by-step explanation:

To find the electric flux through a sphere of radius 5.0 cm with a point charge of -2.0×10-12 C at its center, we can use Gauss's Law. According to Gauss's Law, the electric flux through a closed surface is directly proportional to the charge enclosed by the surface.

Since the charge is located at the center of the sphere, the electric flux passing through the surface of the sphere is the same as the flux passing through a sphere with the same charge at its center. Remember that flux is given by Φ = Q/ε₀, where Q is the charge enclosed and ε₀ is the permittivity of free space.

In this case, the charge is -2.0×10-12 C, so the electric flux through the sphere is Φ = -2.0×10-12 C / ε₀.

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