Final answer:
The heat required to raise the temperature of 3 kg of water from 30°C to 100°C is 880.32 kJ. To convert 30°C to Fahrenheit, the equivalent temperature is 86°F.
Step-by-step explanation:
To find the heat required to raise the temperature of 3 kg of water from 30°C to 100°C, we can use the specific heat capacity formula. The specific heat capacity of water is 4.184 J/g°C. The mass of water needs to be in grams, so we convert 3 kg to 3000 g. The temperature change (ΔT) is 100°C - 30°C = 70°C.
The formula to calculate heat (Q) is:
Q = mcΔT
Where:
- m is the mass of the water,
- c is the specific heat capacity,
- ΔT is the change in temperature.
Plugging in the values, we get:
Q = 3000 g * 4.184 J/g°C * 70°C
So, Q = 880.32 kJ. Thus, 880.32 kJ of heat is required to heat the water.
To express 30°C in the Fahrenheit scale, we use the conversion formula:
F = ¹/₉C + 32
Where:
F is the temperature in Fahrenheit,C is the temperature in Celsius.
To convert 30°C to Fahrenheit:
F = (¹/₉ * 30) + 32
So, F = 86°F. Therefore, 30°C is equivalent to 86°F.