Question

A single wire in the shape of a circle of radius 5.0 cm is carrying a current of 1.8 amps. The wire lies in the xy plane. If the wire is located within a uniform magnetic field of magnitude 0.6 Tesla, what is the net torque on the loop if the magnetic field is oriented parallel to the +x axis

Answer 1

The net torque on the loop is 0 Nm.

Step-by-step explanation:

The net torque on a circular loop carrying a current in a uniform magnetic field can be calculated using the formula:

Torque = N * A * B * sin(theta)

Where N is the number of turns in the loop, A is the area of the loop, B is the magnitude of the magnetic field, and theta is the angle between the magnetic field and the normal to the loop. In this case, there is a single wire in the shape of a circle, so N = 1. The area of the loop can be calculated using the formula A = pi * r^2, where r is the radius of the loop. In this case, the radius is 5.0 cm, so the area is 25 * pi cm^2. The magnetic field is parallel to the +x axis, so the angle theta is 0 degrees. Plugging in the values, we get:

Torque = 1 * (25 * pi) * 0.6 * sin(0) = 0 Nm

Therefore, the net torque on the loop is 0 Nm.