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Find the equation of the axis of symmetry of the following parabola algebraically.

y = x² −14x + 47

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Final answer:

The equation of the axis of symmetry of the parabola y = x² - 14x + 47 is x = 7.

Step-by-step explanation:

The equation of the axis of symmetry of a parabola in the form y = ax² + bx + c is given by the formula x = -b/2a.

In this case, the equation of the parabola is y = x² - 14x + 47. To find the equation of the axis of symmetry, we can substitute the values of a and b into the formula.

x = -(-14)/(2*1)

x = 14/2 = 7.

Therefore, the equation of the axis of symmetry is x = 7.

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