Question

During an experiment, a certain device produces a constant, uniform electric field of

(31.7 N/C) î + (62.5 N/C) ĵ
Nearby, a student holds a large circular hoop with a diameter of 1.25 m such that the hoop is parallel to the x-z plane. What is the electric flux through the hoop?
electric flux:______(N-m²)/C

Answer 1

The electric flux through the hoop can be calculated using the formula Electric Flux = Electric Field * Area * cos(theta). In this case, the electric flux is 9.5507 N-m^2/C.

Step-by-step explanation:

The electric flux through a surface is given by the formula:

Electric Flux = Electric Field * Area * cos(theta)

where Electric Field is the magnitude of the electric field in N/C, Area is the area of the surface in m^2, and theta is the angle between the electric field vector and the normal vector to the surface.

In this case, the hoop is parallel to the x-z plane, so the angle theta is 0 degrees. Therefore, the electric flux through the hoop can be calculated as:

Electric Flux = (31.7 N/C) * (pi * (0.625 m)^2) * cos(0 degrees)

Electric Flux = 31.7 * 0.3011 N-m^2/C

Electric Flux = 9.5507 N-m^2/C