111k views
1 vote
A rubber-wheeled 50 kg cart rolls down a 64° concrete incline. Coefficient of rolling friction between rubber and concrete is Hy = 0.02. What is the cart's acceleration if rolling friction is neglected?

User Steck
by
7.7k points

1 Answer

3 votes

Final answer:

The cart's acceleration when rolling friction is neglected is approximately 9.02 m/s^2.

Step-by-step explanation:

The cart's acceleration when rolling friction is neglected can be found using the force of gravity component along the incline. The force acting down the incline is given by:

F = m * g * sin(theta)

where m is the mass of the cart, g is the acceleration due to gravity, and theta is the angle of the incline.

Substituting the given values, we have:

F = 50 kg * 9.8 m/s^2 * sin(64°)

Solving for F, we get:

F = 450.94 N

Since the force of gravity component is the only force acting down the incline, it is also equal to the net force acting on the cart, which is given by:

F = m * a

where a is the acceleration of the cart.

Substituting the mass and solving for a, we find:

a = F / m

a = 450.94 N / 50 kg

a ≈ 9.02 m/s^2

User DSDmark
by
7.3k points