Question

Find the flux of Earth's magnetic field of magnitude 5.00×10⁻⁵ T through a square loop of area 40.0 cmfield is perpendicular to the plane of the loop T⋅² for field is perpendicular to the plane of the loop T⋅

Answer 1

To calculate the flux of Earth's magnetic field through a square loop, we use the formula for magnetic flux with the magnetic field strength (5.00×10⁻⁵ T), the area of the loop (40.0 cm²), and the fact that the field is perpendicular to the plane of the loop, yielding a flux of 2.00×10⁻⁷ Weber (Wb).

Step-by-step explanation:

To find the flux of Earth's magnetic field through a square loop, we can use the formula for magnetic flux, Φ = B × A × cos(θ), where Φ is the magnetic flux, B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field lines and the normal (perpendicular) to the plane of the loop. In this case, since the magnetic field is perpendicular to the plane of the loop, θ = 0° and cos(θ) = 1. Given that the magnitude 5.00×10⁻⁵ T represents the strength of Earth's magnetic field and the square loop of area 40.0 cm², we can calculate the flux as follows:

Φ = 5.00 × 10⁻⁵ T × 40.0 × 10⁻⁴ m²

= 5.00 × 10⁻⁵ T × 4.00 × 10⁻³ m²

= 2.00 × 10⁻⁷ T·m²

Therefore, the flux through the loop is 2.00 × 10⁻⁷ Weber (Wb).