Question

A curnent density of 7.50×10⁻¹³ A/m³ evists in the atmosphere at a focation where the electric fiela is 120 Vim, Calculate the eiectrical conductivity of the Earths atmasphere in this iegun.

Answer 1

The electrical conductivity of the Earth's atmosphere at the given region, with a current density of 7.50×10⁻¹³ A/m³ and an electric field of 120 V/m, is calculated to be 6.25×10⁻¹⁵ S/m.

Step-by-step explanation:

The electrical conductivity (σ) of the Earth's atmosphere can be calculated using Ohm's Law, where conductivity is the inverse of resistivity (ρ), which is related to the current density (J) and the electric field (E) by the equation J = σE. Given a current density (J) of 7.50×10⁻¹³ A/m³ and an electric field (E) of 120 V/m, we can calculate conductivity using the formula: σ = J/E.

Inserting the given values:

σ = (7.50×10⁻¹³ A/m³) / (120 V/m) = 6.25×10⁻¹⁵ S/m (σ is in Siemens per meter).

Thus, the electrical conductivity of the Earth's atmosphere in this region is 6.25×10⁻¹⁵ S/m.