Question

You are conducting an osmosis experiment with a semi-permeable dialysis membrane of fixed pore size. If the solution temperature rises by 15 C and the coefficient of linear expansion of the regenerated cellulose membrane is 2×10−4 × 10 − 4 K−1 − 1 , how much bigger are the pores in the membrane (by diameter)?

Answer 1

Osmosis and dialysis are processes involving the movement of solvent and solute molecules through a semi-permeable membrane. The size of the pores in the membrane can be calculated using the coefficient of linear expansion of the membrane material and the change in temperature.

Step-by-step explanation:

Osmosis and dialysis are related processes that involve the movement of solvent and solute molecules through a semi-permeable membrane. In osmosis, water moves from an area of lower solute concentration to an area of higher solute concentration, while in dialysis, both solvent and small solute molecules can pass through the membrane. The size of the pores in the membrane determines what can pass through. To calculate the change in pore size in the dialysis membrane, we can use the coefficient of linear expansion of the membrane material and the increase in temperature. The change in diameter of the pores can be found using the formula: Δd = α × d0 × ΔT, where Δd is the change in diameter, α is the coefficient of linear expansion, d0 is the initial diameter, and ΔT is the change in temperature. Given the coefficient of linear expansion and the change in temperature, you can calculate the change in pore size in the membrane.