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A magnetic field, pointed out of the plane of the screen, has a strength of 10 T. Calculate the force (in N ) on the electron travelling downwards with a velocity of 1 m/s.

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Final answer:

The force experienced by the electron can be calculated using the equation F = qvBsinθ, where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field. Plugging in the values, we find that the force on the electron is -1.6 x 10^-18 N (downwards).

Step-by-step explanation:

The force experienced by a charged particle moving in a magnetic field can be calculated using the equation:

F = qvBsinθ

where F is the force, q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

In this case, the electron has a charge of -1.6 x 10^-19 C, a velocity of 1 m/s, and the magnetic field strength is 10 T. Since the electron is moving downwards and the magnetic field is pointing out of the screen, the angle between the velocity and the magnetic field is 90 degrees. Plugging in the values into the equation, we get:

F = (-1.6 x 10^-19 C)(1 m/s)(10 T)(sin 90°) = -1.6 x 10^-18 N

Therefore, the force on the electron is -1.6 x 10^-18 N (downwards).

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