Question

A 1-m³ tank holds a two phase liquid vapor mixture of carbon dioxide at 17°C. The quality of the mixture is 70%. For saturated carbon dioxide at 17°C, vf= 0.9827×10⁻³m³/kg and vg= 1.756×10⁻²m³/kg. Determine the masses of saturated liquid and saturated vapor, each in kg. What is the percent of the total volume occupied by saturated liquid?

Answer 1

The mass of the saturated liquid is 9.827×10⁻⁴ kg and the mass of the saturated vapor is 1.756×10⁻² kg. The percent of the total volume occupied by the saturated liquid is 9.627%.

Step-by-step explanation:

To determine the masses of the saturated liquid and saturated vapor, we can use the formula:

m = V / v

where m is the mass, V is the volume, and v is the specific volume.

Given:

V = 1 m³

For saturated liquid at 17°C, the specific volume vf = 0.9827×10⁻³ m³/kg

For saturated vapor at 17°C, the specific volume vg = 1.756×10⁻² m³/kg

Using the formula:

m₁ (mass of saturated liquid) = V × vf = 1 × 0.9827×10⁻³ = 9.827×10⁻⁴ kg

m₂ (mass of saturated vapor) = V × vg = 1 × 1.756×10⁻² = 1.756×10⁻² kg

To find the percent of the total volume occupied by saturated liquid, we can use the formula:

Percent of volume occupied by liquid = (m₁ × vf) / V × 100%

Percent of volume occupied by liquid = (9.827×10⁻⁴ × 0.9827×10⁻³) / 1 × 100% = 9.627%