Question

Given: Fe₂O₃(s) + 3CO() ---> 2Fe(s) + 3CO₂(g);

Hº = -26.8 kJ

FeO(s) + CO(g) ---> Fe(s) + CO₂(g);
AH°= -16.5 kJ

determine AH° for the following thermochemical equation.

Fe₂O₃(s) + CO(g) --> 2FeO(s) + CO₂(g)

Answer 1

The enthalpy change for the reaction Fe₂O₃(s) + CO(g) -> 2FeO(s) + CO₂(g) is -59.8 kJ.

Step-by-step explanation:

The enthalpy change for the reaction Fe₂O₃(s) + CO(g) -> 2FeO(s) + CO₂(g) can be determined using Hess's law and the given data. We can write two equations that can be added together to give the desired equation:

Fe₂O₃(s) + 3CO(g) -> 2Fe(s) + 3CO₂(g) ΔH° = -26.8 kJ

FeO(s) + CO(g) -> Fe(s) + CO₂(g) ΔH° = -16.5 kJ

By reversing the second equation and multiplying it by 2, we can cancel out the FeO(s) and CO(g) terms and obtain the desired equation.

The enthalpy change for the reaction Fe₂O₃(s) + CO(g) -> 2FeO(s) + CO₂(g) is (-26.8 kJ) + 2*(-16.5 kJ) = -59.8 kJ.