Question

A straight 7.228 m wire carries a current of 0.334 A. If the wire is passed through a region of space with a uniform magnetic field of 0.555 T that makes an angle of 51.77 degrees to the flow of current, what is the magnitude of the force on the wire?

Answer 1

The magnitude of the force on the wire is 1.626 N.

Step-by-step explanation:

The force on a wire carrying a current in a magnetic field can be calculated using the formula:

F = ILBsinθ

Where:
F is the force on the wire
I is the current in the wire
L is the length of the wire
B is the magnetic field strength
θ is the angle between the wire and the magnetic field

In this case, the current is 0.334 A, the length of the wire is 7.228 m, the magnetic field strength is 0.555 T, and the angle is 51.77 degrees. Substituting these values into the formula, we get:

F = (0.334 A)(7.228 m)(0.555 T)sin(51.77°) = 1.626 N

Therefore, the magnitude of the force on the wire is 1.626 N.