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There are two cars in the same lane on the highway, the speed of the rear car is V₂ and the speed of the front car is V1. It is known that V₂>V₁, the rear car starts to brake when it sees the front car, and its acceleration is a, find the minimum value of D so as not to collide.

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Final answer:

The minimum distance D to prevent a collision, when the rear car with initial speed V2 starts to brake with acceleration a, can be calculated using the equation D = V2² / (2a).

Step-by-step explanation:

To determine the minimum distance D required for the rear car not to collide with the car in front, given that the rear car has an initial speed V₂ greater than the front car's speed V₁ and starts to brake with acceleration a, we can use kinematic equations. As the rear car brakes, we must find the point at which it will come to a stop without hitting the car in front.

The stopping distance D can be calculated using the kinematic equation D = V₂² / (2a). This equation assumes the worst-case scenario in which the front car will come to an immediate halt (V₁ = 0) and the rear car will have to brake to a complete stop to avoid a collision.

In a scenario where the second car does not come to a complete stop but maintains a reduced constant velocity, the problem becomes more complex and requires simultaneous equations to solve for both the time and distance before a potential collision occurs.

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