Question

A firefighter holds a hose 3 m off the ground and directs a stream of water toward a burning building. The water leaves the hose at an initial speed of 14 m/s at an angle of 30°. The height of the water can be approximated by h (x)= -0.03x²+0.515x+3, where h (x) is the height of the water in meters at a point x meters horizontally from the firefighter to the building.

Answer 1

The magnitude of the force exerted on the wall by the water from a fire hose can be calculated using Newton's second law of motion. In this case, the force is equal to the mass of the flowing water multiplied by its acceleration. By substituting the given values into the equation, the magnitude of the force is found to be 2100 Newtons.

Step-by-step explanation:

To calculate the magnitude of the force exerted on the wall by the water from a fire hose, we need to use Newton's second law of motion, which states that force equals mass times acceleration. In this case, the mass is the rate at which water is flowing, and the acceleration is the change in velocity.

Given that the rate of water flow is 50.0 kg/s and the speed of the water is 42.0 m/s, we can calculate the mass of the water flowing per second and use it to find the force exerted on the wall.

Using the formula F = ma, where F is the force, m is the mass, and a is the acceleration, we can substitute the values into the equation to calculate the force:

F = (50.0 kg/s) * (42.0 m/s)

F = 2100 N

Therefore, the magnitude of the force exerted on the wall by the water is 2100 Newtons.