162k views
5 votes
A 221.0 g sample of water at 24.5∘C is heated to steam at 139.0∘C. How much heat was absorbed?

User Rzaaeeff
by
7.5k points

1 Answer

2 votes

Final answer:

To calculate the amount of heat absorbed by the water, we can use the equation: q = mcΔT. Substituting the given values into the equation, the heat absorbed is 2.1 × 10² kJ.

Step-by-step explanation:

To calculate the amount of heat absorbed by the water, we can use the equation: q = mcΔT, where q is the heat absorbed, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.

First, calculate the mass of water using the given volume and the density of water at 22.0°C. Then, calculate ΔT by subtracting the initial temperature from the final temperature. Finally, substitute the values into the equation to find the heat absorbed.

Using the equation q = mcΔT, the heat absorbed by the water is 2.1 × 10² kJ.

User PatL
by
7.6k points