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Which number is 10⁵ more than (4×10⁴) (3×10³) (2×10²) (1×10)?

A. 43,260,
b. 53,210,
c. 143,210,
d. 1,432,100

User Sweetdream
by
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1 Answer

6 votes

Final answer:

To find the number that is 10⁵ more than the expression (4×10⁴) (3×10³) (2×10²) (1×10), we first add together the products of each term and then add 100,000. The sum is 143,210, making the correct answer (c) 143,210.

Step-by-step explanation:

To determine which number is 10⁵ more than the given expression (4×10⁴) (3×10³) (2×10²) (1×10), we first need to multiply the terms in the expression together. When we multiply powers of 10 together, we add the exponents. Therefore, the given expression is equivalent to:

4×10⁴ = 4 × 10,000 = 40,000

3×10³ = 3 × 1,000 = 3,000

2×10² = 2 × 100 = 200

1×10¹ = 1 × 10 = 10

Adding these together:

40,000 + 3,000 + 200 + 10 = 43,210

Now, we add 10⁵ (which is 100,000) to this sum:

43,210 + 100,000 = 143,210

The number that is 10⁵ more than the initial expression is 143,210, which corresponds to answer choice (c) 143,210.