Both Ray and Kelsey can be correct depending on how they interpret the term "intercepts".
Let's analyze the polynomial function:
g(x)=(x+2)(x−1)(x−2)
Key features of g(x):
End behavior: As x approaches positive or negative infinity, the value of g(x) approaches positive infinity. This is because the leading term, x^3 , grows much faster than any other term in the polynomial as x increases or decreases without bound.
y-intercept: The y-intercept is the point where the graph of the function crosses the y-axis. This occurs when x=0. Substituting x=0 into the function, we get:
g(0)=(0+2)(0−1)(0−2)=−4
Therefore, the y-intercept is (0,-4).
Zeros: The zeros of the function are the x-values for which g(x)=0. To find the zeros, we can factor the function:
g(x)=(x+2)(x−1)(x−2)
Setting each factor equal to zero and solving for x, we find that the zeros are x=-2, x=1, and x=2.
Addressing Ray and Kelsey's statements:
Ray is correct in saying that the third-degree polynomial can have four intercepts.
This is because the number of intercepts of a polynomial is equal to its degree, which is 3 in this case.
However, Kelsey is also correct in saying that the function can have as many as three zeros only.
This is because the number of zeros of a polynomial is equal to the number of times it can be factored into linear factors.
In this case, the function can be factored into three linear factors, so it has three zeros.
Therefore, both Ray and Kelsey can be correct depending on how they interpret the term "intercepts".