Final answer:
The kinetic energy of a 0.800-kg particle moving at a speed of 1.20 m/s at point (A) is calculated using the formula KE = ½mv², resulting in a kinetic energy of 0.576 Joules.
Step-by-step explanation:
The student has asked for the kinetic energy of a particle at point (A) when its speed is given as 1.20 m/s. To find the kinetic energy at point (A), we can use the formula KE = ½mv², where m is the mass of the particle and v is its velocity. Given that the mass (m) of the particle is 0.800 kg and the velocity (v) at point (A) is 1.20 m/s, the kinetic energy (KE) at point (A) can be calculated as follows:
KE = ½ × 0.800 kg × (1.20 m/s)²
KE = 0.400 kg × 1.44 m²/s²
KE = 0.576 J
Therefore, the kinetic energy of the particle at point (A) is 0.576 Joules.