Question

If the probability the Islanders beat the Rangers in the game is one through three, what is the probability that the Islanders win exactly 3 out of three games in the series against the Rangers? Round your answer to the nearest thousand

Answer 1

The probability of the Islanders winning exactly 3 out of 3 games against the Rangers, with each game having a one-third chance of being won, is about 0.0370.

Step-by-step explanation:

The question revolves around calculating the probability of the Islanders winning 3 out of 3 games against the Rangers, with the probability of winning any single game being one third, or approximately 0.3333 when rounded to four decimal places.

To calculate the probability of three independent events all happening (in this case, winning three games), we multiply the probability of each event occurring. Since the probability of winning a single game is 0.3333, the probability of winning three games is 0.3333 x 0.3333 x 0.3333, which equals approximately 0.0370 when rounded to the nearest thousand.