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The weights of ice cream cartons are normally distributed with a mean weight of 7 ounces and a standard deviation of 0.6 ounce. What is the probability that a randomly selected carton has a weight greater than 7.18 ounces?

User Abulbul
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Final answer:

To find the probability that a randomly selected ice cream carton has a weight greater than 7.18 ounces, calculate the z-score and use a standard normal distribution table or calculator.

Step-by-step explanation:

Given that the weights of ice cream cartons are normally distributed with a mean of 7 ounces and a standard deviation of 0.6 ounce, we can find the probability that a randomly selected carton has a weight greater than 7.18 ounces.

  1. Calculate the z-score for 7.18 ounces using the formula: z = (x - μ) / σ, where x is the given weight, μ is the mean, and σ is the standard deviation.
  2. Substitute the values into the formula: z = (7.18 - 7) / 0.6 = 0.3
  3. Find the probability corresponding to the z-score using a standard normal distribution table or a calculator. The probability of a z-score of 0.3 or greater is approximately 0.3829.

Therefore, the probability that a randomly selected ice cream carton has a weight greater than 7.18 ounces is approximately 0.3829.

User James Skemp
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