Question

A slaughter house bought a number of sheep at Ksh. 1,200 each and a number of cows at Ksh.15,000 each. They paid a total amount of Ksh. 135,000. If they had bought twice as many sheep and three cows less, they would have saved Ksh.15,000. Taking x as the number of sheep bought and y as the number of cows bought.

Form two simultaneous equations in x and y

Answer 1

The solution to the system of equations is x=50 and y=29/6.

Let's solve the system of equations:

1200x+15000y=135000

2400x+12000y=120000

We can solve the system of equations by elimination. First, multiply the top equation by -2:

−2400x−30000y=−270000

Then, add the top and bottom equations together:

−30000y=−145000

y= 29/6

Now that we know y, we can substitute it back into either of the original equations to solve for x. Let's substitute it back into the top equation:

1200x+15000(29/6)=135000

1200x+75000=135000

1200x=60000

x=50

Therefore, the solution to the system of equations is x=50 and y=29/6.