Question

Two teams competed to raise money. Team 1 initially had $25 and collected $5 per day. Team 2 initially had $51 and collected $3 per day. On which day did the teams have the same amount of money?

A. day 26
B. day 8
C. day 38
D. day 13

Answer 1

To find out which day the teams have the same amount of money, set up an equation: 25 + 5d = 51 + 3d. Simplify and solve for d to find that the teams have the same amount of money on day 13.

Step-by-step explanation:

To find out which day the teams have the same amount of money, we need to set up an equation.

Team 1 starts with $25 and collects $5 per day, so the amount of money they have on a given day can be represented by the equation: 25 + 5d, where d is the number of days.

Similarly, Team 2 starts with $51 and collects $3 per day, so the amount of money they have on a given day is represented by the equation: 51 + 3d.

To find the day when the teams have the same amount of money, we need to solve the equation: 25 + 5d = 51 + 3d.

Simplifying the equation, we get 2d = 26, which means d = 13. Therefore, the teams have the same amount of money on day 13.