Question

A proton travels with a speed of 4.90×10⁶ m/s at an angle of 61°

with the direction of a magnetic field of magnitude 0.190 T in the positive x-direction. (a) What is the magnitude of the magnetic force on the proton? N (b) What is the proton's acceleration? m/s²

Answer 1

The magnetic force on a proton in a magnetic field can be calculated using the formula involving its charge, velocity, the magnetic field strength, and the sine of the angle between the velocity and magnetic field direction. To find the acceleration, divide the force by the mass of the proton.

Step-by-step explanation:

To calculate the magnetic force on a proton, we use the formula F = qvBsin(\theta), where F is the force, q is the charge of the proton (1.6 \u00d7 10^-19 C), v is the velocity of the proton, B is the magnetic field strength, and \theta is the angle between the proton's velocity and the direction of the magnetic field.

For a proton traveling at a speed of 4.90\u00d710^6 m/s at an angle of 61\u00b0 with the direction of a magnetic field of magnitude 0.190 T:

1. Calculate the sine of the angle: sin(61\u00b0).
2. Use the previous values to find the magnetic force (F).
3. To find the proton's acceleration (a), use the formula a = F/m, where m is the proton's mass (1.67 \u00d7 10^-27 kg)