Final answer:
The approximate outward force on a 10m × 26m wall during a tornado with an internal pressure of 0.13 atm and an external atmospheric pressure of 1.013 × 10^5 Pa is roughly 2.3 × 10^7 N.
Step-by-step explanation:
To answer the question, the approximate outward force on a 10 m × 26 m wall if a tornado with a pressure of 0.13 atm suddenly envelopes the house, while the atmospheric pressure is 1.013 × 105 Pa, we need to calculate the difference in pressure exerted on the wall from the inside and the outside. Since 1 atm equals to 1.013 × 105 Pa, the pressure inside the tornado can be converted to Pascals (Pa) as 0.13 atm × 1.013 × 105 Pa/atm = 1.3169 × 104 Pa. The force due to pressure differences can now be calculated using the following formula: F = ΔP × A, where ΔP is the difference in atmospheric pressure and pressure inside the tornado, and A is the area of the wall.
First, we find the difference in pressure: ΔP = 1.013 × 105 Pa - 1.3169 × 104 Pa = 8.8121 × 104 Pa. Next, the area of the wall is A = 10 m × 26 m = 260 m2. Thus, the outward force exerted on the wall is F = 8.8121 × 104 Pa × 260 m2 = 2.291146 × 107 N, which can be approximated as 2.3 × 107 N.