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An electron is accelerated through 2.10 x 103 V from rest and then enters a uniform 1.50-T magnetic field. (a) What is the maximum magnitude of the magnetic force this particle can experience? (b) What is the minimum magnitude of the magnetic force this particle can experience?

User Istvan
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Final answer:

To find the maximum and minimum magnitudes of the magnetic force experienced by the electron, we use the equation F = qvBsin(θ). By calculating the charge of the electron and substituting the given values, we can determine the maximum and minimum forces.

Step-by-step explanation:

To determine the maximum and minimum magnitudes of the magnetic force experienced by the electron, we can use the equation F = qvBsin(θ), where F is the force, q is the charge of the electron, v is its velocity, B is the magnetic field strength, and θ is the angle between the velocity and the magnetic field.

(a) Since the electron is accelerated through a voltage, it gains kinetic energy. This kinetic energy can be equated to the work done by the magnetic force. Equating these two, we have (1/2)mv^2 = qvBd, where m is the mass of the electron and d is the distance it travels. Rearranging the equation, we get q = (1/2)mvBd/v^2. Substituting the given values, we can calculate q and then find the maximum magnitude of the magnetic force using F = qvBsin(θ).

(b) Similarly, we can calculate the minimum magnitude of the magnetic force by considering the smallest possible angle between the electron's velocity and the magnetic field.

User Talvalin
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