Question

Calculate the velocity of the target ball after the collision. A ball of mass 0.300 kg that is moving with a speed Express your answer to two significant figures and include the appropriate units. of 5.7 m/s collides head-on and elastically with another ball initially at rest. Immediately after the collision, the incoming ball bounces backward with a speed of 3.6 m/s. Part B Calculate the mass of the target ball.

Answer 1

The velocity of mass B after the collision is 4.0 m/s in the -x-direction.

Step-by-step explanation:

The velocity of mass B after the collision can be determined using the principle of conservation of momentum for an elastic collision. The total momentum before the collision is equal to the total momentum after the collision.

Considering the velocities and masses given in the problem, we can calculate the velocity of mass B:

Mass A initial velocity (v1) = 4.0 m/s

Mass B initial velocity (v2) = 8.0 m/s

Mass A final velocity (v1') = 8.0 m/s (given)

Using the principle of conservation of momentum:

(m1 * v1) + (m2 * v2) = (m1 * v1') + (m2 * v2')

Substituting the known values and solving for v2':

(m1 * v1) + (m2 * v2) = (m1 * v1') + (m2 * v2')

(m1 * 4.0) + (m2 * 8.0) = (m1 * 8.0) + (m2 * v2')

Since the masses are equal in this problem, we can simplify the equation:

4.0 + 8.0 = 8.0 + v2'

12.0 = 8.0 + v2'

v2' = 4.0 m/s