Question

"Starting with one cup of water (250g) at 100∘C, how much

energy does it take to boil it and produce steam at 100∘C?"

Answer 1

To boil one cup of water (250g) and produce steam at 100°C, 565 kJ of energy is needed, calculated using the latent heat of vaporization.

Step-by-step explanation:

To calculate the amount of energy needed to boil one cup of water and produce steam at 100°C, we use the latent heat of vaporization of water. The latent heat of vaporization for water at 100°C is about 2260 kJ/kg. Since we have 250 g of water, which is 0.25 kg, we multiply this by the latent heat of vaporization to find the amount of energy required.

Energy needed = mass of water (kg) × latent heat of vaporization (kJ/kg)

Energy needed = 0.25 kg × 2260 kJ/kg = 565 kJ

Therefore, it takes 565 kJ of energy to boil one cup of water (250g) and turn it into steam at 100°C.