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Calculate the mass of a door closing at 0.2m/s with a kinetic energy of 1.6J___

User Rkok
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1 Answer

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Final answer:

The mass of the door closing at 0.2m/s with a kinetic energy of 1.6J is 16 kg.

Step-by-step explanation:

In order to calculate the mass of the door, we can use the equation for kinetic energy:

KE = (1/2)mv^2

Given that the kinetic energy of the door is 1.6 J and its velocity is 0.2 m/s, we can rearrange the equation to solve for the mass:

m = (2KE) / v^2

Plugging in the values, we get:

m = (2 * 1.6 J) / (0.2 m/s)^2

m = 16 kg

Therefore, the mass of the door is 16 kg.

User Kushal Maniyar
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