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What sample size is needed to estimate a population mean within \pm 60 of the true mean value using a confidence level of 95%, if the true population variance is known to be 140,625 ?

User Yahyazini
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Final answer:

To estimate a population mean within ± 60 of the true mean value using a confidence level of 95%, a sample size of at least 182 is needed.

Step-by-step explanation:

To estimate a population mean within ± 60 of the true mean value using a confidence level of 95%, we need to determine the required sample size. The formula to calculate the sample size is:

n = (Z² * σ²) / E²

Where:
n is the required sample size,
Z is the Z-score corresponding to the chosen confidence level (in this case, it is 1.96 for 95% confidence),
σ is the known population variance (140,625 in this case), and
E is the desired margin of error (60 in this case).

Substituting the values into the formula, we get:
n = (1.96² * 140,625) / 60² = 181.44.

Therefore, we would need a sample size of at least 182 to estimate the population mean within ± 60 with 95% confidence.

User Franklin Piat
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