Question

Use the following information to answer question:

A bag contains 2 red marbles, 6 white marbles, and 5 blue marbles. A single marble is chosen at random. Let A and B represent the following events: A: A red marble is drawn. B: A white marble is drawn. According to this information, events A and B must be events, and the probability of A or B is ii 27. The statement above is completed by the information in row. Use the following information to answer question 28 Two containers are on a table. The first container has eards with the ietters Q, H. I. and B. The second container has cards with the digits I to 5 . The following
A) P(H)+P(3)
B) P(H)×P(3)
C) P(H)+P(3)−P(H and 3)
D) P(H)×P(3)−P(H and 3)

Answer 1

The completed statement is P(H)+P(3)−P(H and 3). The expression evaluates to 11/13.

Step-by-step explanation:

The statement, according to the information given, is completed by the expression: P(H)+P(3)−P(H and 3).

To calculate this expression, we need to find the individual probabilities of event H and event 3, as well as the probability of both events occurring (H and 3).

The probability of event H, which represents drawing a white marble, can be found by dividing the number of white marbles (6) by the total number of marbles (13). So, P(H) = 6/13.

The probability of event 3, which represents drawing a blue marble, can be found by dividing the number of blue marbles (5) by the total number of marbles (13). So, P(3) = 5/13.

The probability of both events occurring can be found by dividing the number of marbles that are both white and blue (0) by the total number of marbles (13). So, P(H and 3) = 0/13.

Now we can substitute these values into the expression P(H)+P(3)−P(H and 3): P(H)+P(3)−P(H and 3) = (6/13) + (5/13) - (0/13) = 11/13.